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Calculating $ \boldsymbol {\lambda _\nu }$

Equation 23 is evaluated numerically to yield a look up table of values for different degrees of freedom. To aid calculation we change the limits as follows

$\displaystyle \lambda_\nu$ $\displaystyle = \frac{1}{(\nu - 1)(\nu - 2)} \int_{-\infty}^{\infty} \frac{(t^2+\nu-1)^2T_\nu(t)^3}{p(t)^2} dt,$ (25)
     
  let $ w$ = $ 1/t$ so that $ dt = -w^{-2}dw$ giving    
     
  $\displaystyle = \frac{2}{(\nu - 1)(\nu - 2)} \left( \int_0^1 \frac{(t^2+\nu-1)^...
...}{p(t)^2}dt + \int_0^1 \frac{({1/w}^2+\nu-1)^2T_\nu(1/w)^3}{p(1/w)^2}dw \right)$ (26)



David Flitney 2001-11-29