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Case 2: $ B^{(0)}(\mathbf{x}) = (1,0,0)$

 


$\displaystyle F(\mathbf{x}';\mathbf{x})$ $\displaystyle =$ $\displaystyle \iiint \frac{\partial^2 G}{\partial x' \partial z'} \, dx' \, dy' \, dz'$  
  $\displaystyle =$ $\displaystyle \int G \, dy'$  
  $\displaystyle =$ $\displaystyle \frac{-1\,}{4\pi} \mathrm{sinh}^{-1}\left(\frac{y'}{\sqrt{{x'}^2 + {z'}^2}}\right)$ (23)

using equation 29 from Appendix A.

Again, this can be substituted into equations 14 and 21 to get $ B^{(1)}_z$.