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Normalisation

Let an unnormalised voxel time series be denoted by $R_t(\ensuremath{\mathbf{x}})$ where $t = 1,\ldots,N_T$ is the time index. Treating this as a time-vector (that is, an $N_T$ by 1 matrix), SPM performs a ``normalisation'':

\begin{displaymath}
S_t(\ensuremath{\mathbf{x}}) = \frac{R_t(\ensuremath{\mathbf...
...T} R_t(\ensuremath{\mathbf{x}}) R_t(\ensuremath{\mathbf{x}})}}
\end{displaymath} (37)

or, by suppressing indices and using matrix notation, as $S = R / \sqrt{R^\top R}$.

This ``normalisation'' results in the expected sum of the residuals squared being unity. Therefore, the expected value for any particular residual squared is actually:

\begin{displaymath}
E\{ ( S_t(\ensuremath{\mathbf{x}}) \, )^2 \} = \frac{1}{N_T}.
\end{displaymath} (38)

Consequently, the factor $k$, introduced previously needs to be divided by $\sqrt{N_T}$. This also means that, when taking the sum over the possible time points, it is no longer necessary to normalise the sum. Therefore, the full 4D average for $\lambda$, assuming no temporal correlation, is:

\begin{displaymath}
\lambda_{11} = \frac{1}{N} \sum_{\ensuremath{\mathbf{x}}} \s...
...{\partial S_t(\ensuremath{\mathbf{x}})}{\partial x} \right)^2.
\end{displaymath} (39)



Mark Jenkinson 2001-11-07